A string of mass 2.5, kg under some tension. The length of stretched string is 20, m . If the&n

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14.Waves and Sound

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A string of mass $2.5\, kg$ under some tension. The length of the stretched string is $20\, m$. If the transverse jerk produced at one end of the string takes $0.5\, s$ to reach the other end, tension in the string is .... $N$

A

$100$

B

$200$

C

$300$

D

$400$

Solution

$v=\frac{S}{t}=\frac{20}{.5}=40 \mathrm{\,m} / \mathrm{s}$

now $T=v^{2} \times \mu=(40)^{2} \times \frac{2.5}{20}=200 \mathrm{N}$

$V=\sqrt{\frac{T}{\mu}}=\sqrt{\frac{T}{m / \ell}}, 40=\sqrt{\frac{T \times 20}{2.5}}$

$\mathrm{T}=200 \mathrm{\,N}$

Standard 11

Physics

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