Two waves represented by y₁ = a,sin(omega,t) and y₂ = b, cos, (omega, t) have a phase difference

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14.Waves and Sound

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The two waves represented by $y_1 = a\,sin(\omega\,t)$ and $y_2 = b\, cos\, (\omega\, t)$ have a phase difference of

A

$0$

B

$\frac{\pi }{2}$

C

$\pi$

D

$\frac{\pi }{4}$

Solution

$y_1=a \sin \omega t, \text { and } y_2=b \cos \omega t=b \sin \left(\omega t+\frac{\pi}{2}\right)$

So phase difference $\phi=\pi / 2$

Standard 11

Physics

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