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6.Interest
hard
A sum of ₹ $12,000$ deposited at compound interest becomes double after $5$ years. After $20$ years, it will become (In ₹)
A
$48000$
B
$96000$
C
$190000$
D
$192000$
Solution
(d) $A=P\left(1+\frac{R}{100}\right)^{T}$
$\Rightarrow \frac{A}{P}=\left(1+\frac{R}{100}\right)^{T}$
$\Rightarrow \quad 2=\left(1+\frac{R}{100}\right)^{5}$
$\Rightarrow 2^{4}=\left(1+\frac{R}{100}\right)^{20}$
$\Rightarrow 16=\left(1+\frac{R}{100}\right)^{20}$
Hence, the principal will become 16 times in 20 years. $=₹(16 \times 12000)$
$=₹ 1,92,000$
Standard 13
Quantitative Aptitude