A sum of ₹ 12,000 deposited at compound inter | vedclass

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Question

(d) $A=P\left(1+\frac{R}{100}\right)^{T}$

$\Rightarrow \frac{A}{P}=\left(1+\frac{R}{100}\right)^{T}$

$\Rightarrow \quad 2=\left(1+\frac{R}{100}\

Vedclass · Accepted Answer

$192000$

Vedclass · Answer

(d) $A=P\left(1+\frac{R}{100}ight)^{T}$

$\Rightarrow \frac{A}{P}=\left(1+\frac{R}{100}ight)^{T}$

$\Rightarrow \quad 2=\left(1+\frac{R}{100}ight)^{5}$

$\Rightarrow 2^{4}=\left(1+\frac{R}{100}ight)^{20}$

$\Rightarrow 16=\left(1+\frac{R}{100}ight)^{20}$

Hence, the principal will become 16 times in 20 years. $=₹(16 	imes 12000)$

$=₹ 1,92,000$

A sum of ₹ $12,000$ deposited at compound interest becomes double after $5$ years. After $20$ years, it will become (In ₹)

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