A tangent galvanometer has a coil of 25 turns and a radius of 15, cm . horizontal component of earth

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5.Magnetism and Matter

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A tangent galvanometer has a coil of $25$ $turns$ and a radius of $15\, cm$. The horizontal component of the earth’s magnetic field is $3\times10^{-5}\, T$. The current required to produce a deflection of $45^o$ in it is....$A$

A

$0.29$

B

$1.2$

C

$3.6\times10^{-5}$

D

$0.14$

Solution

In a tangent galvanometer,

$i=\frac{2 r B_{H}}{\mu_{0} N} \tan \theta$

$\therefore i=\frac{2 \times 15 \times 10^{-2} \times 3 \times 10^{-5}}{4 \pi \times 10^{-7} \times 25} \times \tan 45^{\circ}$

$=0.29 A$

Standard 12

Physics

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