Gujarati
5.Magnetism and Matter
medium

The radius of the coil of a Tangent galvanometer. which has $ 10 $ $turns$ is $0.1\,m. $ The current required to produce a deflection of $60°$  $({B_H} = 4 \times {10^{ - 5}}\,T)$ is.....$A$

A

$3$

B

$1.1$

C

$2.1$

D

$1.5$

Solution

(b)$B = {B_H}\tan \theta $ $==>$ $\frac{{{\mu _0}ni}}{{2r}} = {B_H}\tan \theta $
$==>$ $i = \frac{{2r.\;{B_H}\tan \theta }}{{{\mu _0}n}}$$ = \frac{{2 \times 0.1 \times 4 \times {{10}^{ – 5}}}}{{10 \times 4\pi \times {{10}^{ – 7}}}}$$= 1.1\,A$
 

Standard 12
Physics

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