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A thermodynamic process is shown in the figure. The pressures and volumes corresponding to some points in the figure are :
${P_A} = 3 \times {10^4}Pa,\;{P_B} = 8 \times {10^4}Pa$ and ${V_A} = 2 \times {10^{ - 3}}{m^3},\;{V_D} = 5 \times {10^{ - 3}}{m^3}$
In process $AB$, $600 J$ of heat is added to the system and in process $BC, 200 J $ of heat is added to the system. The change in internal energy of the system in process $ AC$ would be ...... $J$

$560$
$800 $
$600 $
$640 $
Solution
(a) By adjoining graph ${W_{AB}} = 0$ and
${W_{BC}} = 8 \times {10^4}[5 – 2] \times {10^{ – 3}} = 240\,J$
${W_{AC}} = {W_{AB}} + {W_{BC}} = 0 + 240 = 240\,J$
Now, $\Delta {Q_{AC}} = \Delta {Q_{AB}} + \Delta {Q_{BC}} = 600 + 200 = 800\,J$
From FLOT $\Delta {Q_{AC}} = \Delta {U_{AC}} + \Delta {W_{AC}}$
==> $800 = \Delta {U_{AC}} + 240$ ==> $\Delta {U_{AC}} = 560\,J.$
Similar Questions
$List I$ describes thermodynamic processes in four different systems. $List II$ gives the magnitudes (either exactly or as a close approximation) of possible changes in the internal energy of the system due to the process.
$List-I$ | $List-II$ |
($I$) $10^{-3} kg$ of water at $100^{\circ} C$ is converted to steam at the same temperature, at a pressure of $10^5 Pa$. The volume of the system changes from $10^{-6} m ^3$ to $10^{-3} m ^3$ in the process. Latent heat of water $=2250 kJ / kg$. | ($P$) $2 kJ$ |
($II$) $0.2$ moles of a rigid diatomic ideal gas with volume $V$ at temperature $500 K$ undergoes an isobaric expansion to volume $3 V$. Assume $R=8.0 Jmol ^1 K^{-1}$. | ($Q$) $7 kJ$ |
($III$) On mole of a monatomic ideal gas is compressed adiabatically from volume $V=\frac{1}{3} m^3$ and pressure $2 kPa$ to volume $\frac{v}{8}$ | ($R$) $4 kJ$ |
($IV$) Three moles of a diatomic ideal gas whose molecules can vibrate, is given $9 kJ$ of heat and undergoes isobaric expansion. | ($S$) $5 kJ$ |
($T$) $3 kJ$ |
Which one of the following options is correct?