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11.Thermodynamics
medium
A thermodynamic process is the pressure and volumes corresponding to some points in the figure are, $P_A = 3 \times 10^4 Pa$, $V_A = 2 \times 10^{-3}\, m^3$, $P_B = 8 \times 10^4 Pa$, $V_D = 5 \times 10^{-3}\,m^3$. In process $AB, 600\, J$ of heat and in process $BC, 200\, J$ of heat is added to the system. The change in the internal energy in process $AC$ would be .... $J$
A
$560$
B
$800$
C
$600$
D
$640$
Solution
$\Delta \mathrm{U}_{\mathrm{AC}}=\Delta \mathrm{U}_{\mathrm{AC}}+\mathrm{W}_{\mathrm{AC}}$
$(600+200)=\Delta \mathrm{U}_{\mathrm{AC}}+\left[8 \times 10^{4}(5-2) \times 10^{-3}\right]$
$\Delta \mathrm{U}_{\mathrm{AC}}=800-240$
$=560$ Jule.
Standard 11
Physics
