A thin circular ring of mass M and radius R i | vedclass

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Question

Angular momentum, $L=I \omega$

$\Rightarrow L=M R^2 W\left(\because I=M R^2\right)$

On attaching two objects, each of man $m$ gently to the oppo

Vedclass · Accepted Answer

$\frac{{\omega M}}{{M + 2m}}$

Vedclass · Answer

Angular momentum, $L=I \omega$

$\Rightarrow L=M R^2 W\left(\because I=M R^2\right)$

On attaching two objects, each of man $m$ gently to the opposite ends of diamiter of the ring,

$I^{\prime} =M R^2+2\left(M R^2\right)$

$\Rightarrow I^{\prime} =(M+2 M) R^2$

Angular momentum, $L^{\prime}=T^{\prime} \omega^{\prime}$

$\rightarrow L^{\prime}=(M+2 m) R^2 W^{\prime}$

Now, as no extunal torque is applied on the ming, its angular momentum will be consurved

$\Rightarrow L^{\prime}=L$

$\Rightarrow(M+2 M) R^{\prime} W^{\prime}=M R^2 \omega$

$\Rightarrow W^{\prime}=\frac{\omega M}{M+2 m}$

Menu, the ming will finally rotale with an angular vulocity of $\frac{w M}{M+2 m}$

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