Gujarati
Hindi
1. Electric Charges and Fields
normal

A thin spherical conducting shell of radius $R$ has a charge $q.$ Another charge $Q$ is placed at the centre of the shell. The electrostatic potential at a point $p$ a distance $R/2$ from the centre of the shell is

A

$\frac{{\left( {q + Q} \right)2}}{{4\pi { \in _0}R}}$

B

$\frac{{2Q}}{{4\pi { \in _0}R}}$

C

$\frac{{2Q}}{{4\pi { \in _0}R}} - \frac{{2q}}{{4\pi { \in _0}R}}$

D

$\frac{{2Q}}{{4\pi { \in _0}R}} + \frac{{q}}{{4\pi { \in _0}R}}$

Solution

Electric potential at $\mathrm{P}$

$\mathrm{V}=\frac{\mathrm{K} \mathrm{Q}}{\mathrm{R} / 2}+\frac{\mathrm{k} \cdot \mathrm{q}}{\mathrm{R}}$

$ = \frac{{2{\rm{Q}}}}{{4\pi { \in _0}{\rm{R}}}} + \frac{{\rm{q}}}{{4\pi { \in _0}{\rm{R}}}}$

Standard 12
Physics

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