A truck is moving on a straight road with uniform acceleration. The following table gives the speed of the truck at various instants of time.

Speed $\left(m s^{-1}\right)$ $5$ $10$ $15$ $20$ $25$ $30$
Time $(s)$ $0$ $10$ $20$ $30$ $40$ $50$

Draw the speed-time graph by choosing a convenient scale. Determine from it

$(i)$ the acceleration of truck

$(ii)$ the distance travelled by the truck in $50$ seconds.

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The graph is as shown

$(i)$ Acceleration can be obtained by finding the slope of graph $AB$

Slope $=\frac{B C}{A C}=\frac{30-5}{50-0}=0.5 m s ^{-2}$

$(ii)$ Distance travelled by truck $=$ Area of trapezium $OABD$

$=1 / 2 \times$ sum of parallel sides $\times$ perpendicular distance

$=1 / 2 \times( AO + BD ) \times OD$

$=1 / 2 \times(5+30) \times 50=875 m$

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