A uniform chain of length L changes partly from a table which is kept in equilibrium by friction. ma

English

Gujarati

Hindi

4-2.Friction

easy

A uniform chain of length $L$ changes partly from a table which is kept in equilibrium by friction. The maximum length that can withstand without slipping is $l$, then coefficient of friction between the table and the chain is

A$\frac{l}{L}$

B$\frac{l}{{L + l}}$

C$\frac{l}{{L - l}}$

D$\frac{L}{{L + l}}$

Solution

(c) $\mu = \frac{{{\rm{Lenght \,of \,chain\, hanging \,from \,the \,table}}}}{{{\rm{Lenght\, of\, chain \,lying \,on \,the \,table}}}}$ $ = \frac{l}{{L – l}}$

Standard 11

Physics

Static friction between two surfaces

easy

Someone is using a scissors to cut a wire of circular cross section and negligible weight. The wire slides in the direction away from the hinge until the angle between the scissors blades becomes $2 \alpha$. The friction coefficient between the blades and the wire, is :-

hard

A block of mass $4\,kg$ is placed on a rough horizontal plane A time dependent force $F = kt^2$ acts on the block, where $k = 2\,N/s^2$. Coefficient of friction $\mu = 0.8$. Force of friction between block and the plane at $t = 2\,s$ is ……. $N$

medium

Find the minimum value of $m$ that should placed on $20\, kg$, so that system remain at rest …….. $kg$

medium

Why are mountain roads generally made winding upwards rather than going straight up ?

easy

A uniform chain of length $L$ changes partly from a table which is kept in equilibrium by friction. The maximum length that can withstand without slipping is $l$, then coefficient of friction between the table and the chain is

Solution

Similar Questions

Static friction between two surfaces

Someone is using a scissors to cut a wire of circular cross section and negligible weight. The wire slides in the direction away from the hinge until the angle between the scissors blades becomes $2 \alpha$. The friction coefficient between the blades and the wire, is :-

A block of mass $4\,kg$ is placed on a rough horizontal plane A time dependent force $F = kt^2$ acts on the block, where $k = 2\,N/s^2$. Coefficient of friction $\mu = 0.8$. Force of friction between block and the plane at $t = 2\,s$ is ……. $N$

Find the minimum value of $m$ that should placed on $20\, kg$, so that system remain at rest …….. $kg$

Why are mountain roads generally made winding upwards rather than going straight up ?

Start a Free Trial Now