A uniform magnetic field $B$ is acting from south to north and is of magnitude $1.5$ $Wb/{m^2}$. If a proton having mass $ = 1.7 \times {10^{ - 27}}\,kg$ and charge $ = 1.6 \times {10^{ - 19}}\,C$ moves in this field vertically downwards with energy $5\, MeV$, then the force acting on it will be
$7.4 \times {10^{12}}\,N$
$7.4 \times {10^{ - 12}}\,N$
$7.4 \times {10^{19}}\,N$
$7.4 \times {10^{ - 19}}\,N$
An electron enters a chamber in which an uniform magnetic field is present as shown in figure. Ignore gravity. During its motion inside the chamber
A current of $i$ ampere is flowing in an equilateral triangle of side $a$. The magnetic induction at the centroid will be
A proton and an $\alpha$ -particle, having kinetic energies $K _{ p }$ and $K _{\alpha},$ respectively, enter into $a$ magnetic field at right angles.
The ratio of the radii of trajectory of proton to that of $\alpha$ -particle is $2: 1 .$ The ratio of $K _{ p }: K _{\alpha}$ is :
A charge moving with velocity $v$ in $X$-direction is subjected to a field of magnetic induction in the negative $X$-direction. As a result, the charge will
A very high magnetic field is applied to a stationary charge. Then the charge experiences