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6.System of Particles and Rotational Motion
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A uniform rod of length $L$ and weight $W$ is suspended horizontally by two vertical ropes as shown. The first rope is attached to the left end of the rod while the second rope is attached a distance $L /4$ from the right end. The tension in the second rope is

A
$\frac{W}{2}$
B
$\frac{W}{4}$
C
$\frac{W}{3}$
D
$\frac{{2W}}{3}$
Solution

$T_{1}+T_{2}=W$
Taking moment about $A .[C . W . \oplus)$
$W \times \frac{L}{2}-T_{2} \times \frac{3 L}{4}=0$
$T_{2}=\frac{\overline{2} W}{3}$
Standard 11
Physics
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