A vector $\vec Q$ which has a magnitude of $8$ is added to the vector $\vec P$ which lies along $x-$ axis. The resultant of two vectors lies along $y-$ axis and has magnitude twice that of $\vec P$. The magnitude of is $\vec P$
$\frac {6}{\sqrt 5}$
$\frac {8}{\sqrt 5}$
$\frac {12}{\sqrt 5}$
$\frac {16}{\sqrt 5}$
Explain resolution of vector in two dimension. Explain resolution of vector in its perpendicular components.
The magnitude of the $X$ and $Y$ component of $\vec A$ are $7$ and $6$ respectively. Also the magnitude of $X$ and $Y$ component of $\vec A + \vec B$ are $11$ and $9$ respectively. What is the magnitude of $\vec B$ ?
Four forces are acting at a point $P$ in equilibrium as shown in figure. The ratio of force $F_{1}$ to $F_{2}$ is $1: x$ where $x =....$
Two forces $P + Q$ and $P -Q$ make angle $2 \alpha$ with each other and their resultant make $\theta$ angle with bisector of angle between them. Then :