A vector overrightarrow a is turned without | vedclass

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Question

(b) From the figure $|\overrightarrow {OA} |\, = a$ and $|\overrightarrow {OB} |\, = a$

Also from triangle rule

$\overrightarrow {OB} - \overrig

Vedclass · Accepted Answer

$a\,d	heta ,\,0\,$

Vedclass · Answer

(b) From the figure $|\overrightarrow {OA} |\, = a$ and $|\overrightarrow {OB} |\, = a$

Also from triangle rule

$\overrightarrow {OB} - \overrightarrow {OA} = \overrightarrow {AB} = \Delta \overrightarrow {a\,} $ $ \Rightarrow \,\,\,|\Delta \overrightarrow {a\,} |\, = AB$
Using angle $ = \frac{{{m{arc}}}}{{{m{radius}}}}$

$&rArr; AB = a . d 	heta$

So $|\Delta \overrightarrow {a\,} |\, = \,a\,d	heta $

$\Delta a$ means change in magnitude of vector i.e.

$|\overrightarrow {OB} | - |\overrightarrow {OA} | \Rightarrow \,\,\,a - a = 0$

So $\Delta a = 0$

A vector $\overrightarrow a $ is turned without a change in its length through a small angle $d\theta .$The value of $|\Delta \overrightarrow a |$ and $\Delta a$ are respectively

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