A vehicle is moving with speed v on a curved | vedclass

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Question

(c)

On a banked road,

Resolving forces in horizontal and vertical directions, we have

$R \sin 	heta+f \cos 	heta=\frac{m v^2}{r}$

and $R

Vedclass · Accepted Answer

$	an 	heta=\frac{v^2-\mu r g}{r g+\mu v^2}$

Vedclass · Answer

(c)

On a banked road,

Resolving forces in horizontal and vertical directions, we have

$R \sin 	heta+f \cos 	heta=\frac{m v^2}{r}$

and $R \cos 	heta-f \sin 	heta =m g$ $\Rightarrow \quad \frac{R \sin 	heta+f \cos 	heta}{R \cos 	heta-f \sin 	heta}=\frac{v^2}{r g}$

$\Rightarrow \frac{	an 	heta+f / R}{1-f / R 	an 	heta}=\frac{v^2}{r g}$

$\Rightarrow \frac{	an 	heta+\mu}{1-\mu 	an 	heta}=\frac{v^2}{r g}$

$\Rightarrow \left(\mu v^2+r gight) 	an 	heta=v^2-\mu r g$

$\Rightarrow 	an 	heta=\frac{v^2-\mu r g}{\mu v^2+r g}$

A vehicle is moving with speed $v$ on a curved road of radius $r$. The coefficient of friction between the vehicle and the road is $\mu$. The angle $\theta$ of banking needed is given by

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