4-2.Friction
hard

What is the maximum value of the force $F$ such that the block shown in the arrangement, does not move ........ $N$

A

$20$

B

$10$

C

$12$

D

$15$

(IIT-2003)

Solution

(a) $f = \mu R$

$F\cos 60^\circ = \mu (W + F\sin 60^\circ )$

Substituting $\mu = \frac{1}{{2\sqrt 3 }}$ & $W = 10\sqrt 3 $

we get $F = 20\,N$

Standard 11
Physics

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