Gujarati
4-1.Newton's Laws of Motion
easy

A vehicle of $100\, kg$ is moving with a velocity of $5 \,m/sec$. To stop it in $\frac{1}{{10}}\sec $, the required force in opposite direction is ........... $N$

A

$5000$

B

$500$

C

$50$

D

$1000$

Solution

(a)$F = m\;\left( {\frac{{dv}}{{dt}}} \right) = \frac{{100 \times 5}}{{0.1}} = 5000\;N$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.