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4-1.Newton's Laws of Motion
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A vehicle of $100\, kg$ is moving with a velocity of $5 \,m/sec$. To stop it in $\frac{1}{{10}}\sec $, the required force in opposite direction is ........... $N$
A
$5000$
B
$500$
C
$50$
D
$1000$
Solution
(a)$F = m\;\left( {\frac{{dv}}{{dt}}} \right) = \frac{{100 \times 5}}{{0.1}} = 5000\;N$
Standard 11
Physics
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