Gujarati
10-1.Thermometry, Thermal Expansion and Calorimetry
medium

A vessel contains $110\, g$ of water. The heat capacity of the vessel is equal to $10\, g$ of water. The initial temperature of water in vessel is $10°C.$ If $220\, g$ of hot water at $70°C$ is poured in the vessel, the final temperature neglecting radiation loss, will be........ $^oC$

A

$70$

B

$80$

C

$60$

D

$50$

Solution

(d) Let final temperature of water be $\theta$

Heat taken $=$ Heat given

$110 \times 1 (\theta -10) + 10 (\theta -10) = 220 \times 1 (70 -\theta)$

==> $\theta  = 48.8°C \approx  50°C.$

Standard 11
Physics

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