4-1.Newton's Laws of Motion
medium

A weight $M g$ is suspended from the middle of a rope whose ends are at the same level. The rope is no longer horizontal. The minimum tension required to completely straighten the rope is ......

A

$\frac{M g}{2}$

B

$M g \cos \theta$

C

$2 M g \cos \theta$

D

Infinitely large

Solution

(d)

$2 T \cos \theta =m g$

$T=\frac{m g}{2 \cos \theta} \ldots(i)$

To make this string completely straight

in $(i)$ put $\theta=90^{\circ}$

$T=\frac{m g}{2 \cos 90^{\circ}} \approx \infty$

Standard 11
Physics

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