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4-1.Newton's Laws of Motion
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A weight $M g$ is suspended from the middle of a rope whose ends are at the same level. The rope is no longer horizontal. The minimum tension required to completely straighten the rope is ......
A
$\frac{M g}{2}$
B
$M g \cos \theta$
C
$2 M g \cos \theta$
D
Infinitely large
Solution

(d)
$2 T \cos \theta =m g$
$T=\frac{m g}{2 \cos \theta} \ldots(i)$
To make this string completely straight
in $(i)$ put $\theta=90^{\circ}$
$T=\frac{m g}{2 \cos 90^{\circ}} \approx \infty$
Standard 11
Physics
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