A mass of 10,kg is suspended vertically by a rope from roof. When a horizontal force is applied on r

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4-1.Newton's Laws of Motion

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A mass of $10\,kg$ is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of $45^o$ at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is .......... $N$ $(g = 10\,ms^{-2})$

A

$200$

B

$140$

C

$70$

D

$100$

(JEE MAIN-2019)

Solution

$T\,\,cos\,45^o = mg$
$T\,\,sin\,45^o = F$
$\Rightarrow F = mg = 100\,N.$

Standard 11

Physics

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