A wheel is of diameter $1\ m.$ If it makes $30$ revolution per second, then the linear speed of a point on its circumference will be
$30\,\,\pi \,\,\,m/s$
$\pi \,\,\,m/s$
$60\,\,\pi \,\,\,m/s$
$\frac{\pi }{2}\,\,\,m/s$
A grinding wheel attained a velocity of $20\,rad/sec$ in $5\,sec$ starting from rest. Find the number of revolution made by the wheel
Consider the two statements related to circular motion in usual notations
$A$. In uniform circular motion $\vec{\omega}, \vec{v}$ and $\vec{a}$ are always mutually perpendicular
$B$. In non-uniform circular motion, $\vec{\omega}, \vec{v}$ and $\vec{a}$ are always mutually perpendicular
If ${a_r}$ and ${a_t}$represent radial and tangential accelerations, the motion of a particle will be uniformly circular if
A particle is moving on a circular path of radius $r$ with uniform velocity $v$. The change in velocity when the particle moves from $P$ to $Q$ is $(\angle POQ = 40^\circ )$
particle is moving in a circular path. The acceleration and momentum of the particle at a certain moment are $\vec a\, = \,(4\hat i + 3\hat j)\,\,m/{s^2}$ and $\vec P\, = \,(8\hat i\, - \,6\hat j)\,kg\, - \,m/s$ . The motion of the particle is