8.Mechanical Properties of Solids
medium

A wire is suspended by one end. At the other end a weight equivalent to $20\, N$ force is applied. If the increase in length is $1.0\, mm$, the increase in energy of the wire will be .......  $joule$

A

$0.01$

B

$0.02$

C

$0.04$

D

$1.00$

Solution

(a) Increase in energy $ = \frac{1}{2} \times 20 \times 1 \times {10^{ – 3}} = 0.01J$

Standard 11
Physics

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