A wire of area of cross-section 10^{-6},m^2 is increased in length by 0.1% . tension produced is 100

English

Gujarati

Hindi

8.Mechanical Properties of Solids

easy

A wire of area of cross-section $10^{-6}\,m^2$ is increased in length by $0.1\%$. The tension produced is $1000\, N$. The Young's modulus of wire is

A

$10^{12}\, N/m^2$

B

$10^{11}\, N/m^2$

C

$10^{10}\, N/m^2$

D

$10^{9}\, N/m^2$

Solution

$Y = \frac{{FL}}{{Al}} = \frac{{1000 \times 100}}{{{{10}^{ – 6}} \times 0.1}} = {10^{12}}\,N/{m^2}$

Standard 11

Physics

Share

Similar Questions

Which of the following statements is correct

easy

A load $W$ produces an extension of $1mm$ in a thread of radius $r.$ Now if the load is made $4W$ and radius is made $2r$ all other things remaining same, the extension will become….. $mm$

medium

A fixed volume of iron is drawn into a wire of length $L.$ The extension $x$ produced in this wire by a constant force $F$ is proportional to

medium

A bar is subjected to axial forces as shown. If $E$ is the modulus of elasticity of the bar and $A$ is its crosssection area. Its elongation will be

hard

A copper wire of length $2.2 \;m$ and a steel wire of length $1.6\; m ,$ both of diameter $3.0 \;mm ,$ are connected end to end. When stretched by a load, the net elongation is found to be $0.70 \;mm$. Obtain the load applied in $N$.

medium