A woman with two genes for haemophillia and one gene for colourblindness on one of the $X$ chromosomes marries a normal man. How will the progeny be
A woman with two genes for haemophillia and one gene for colourblindness on one of the $X$ chromosomes marries a normal man. How will the progeny be
- [AIPMT 1998]
- A
All sons and daughters haemophillic and colourblind
- B
Haemophillic and colourblind daughters
- C
$50\%$ haemophillic colourblind sons and $50\%$ normal sons
- D
$50\%$ haemophillic daughters and $50\%$ colourblind daughters
Similar Questions
In the following human pedigree, the filled symbols represent the affected individuals. Identify the type of given pedigree.
In the following human pedigree, the filled symbols represent the affected individuals. Identify the type of given pedigree.
- [NEET 2015]
In the above pedigree, assume that no outsider marrying in, carry a disease. Write the genotypes of $C$ and $D$.
In the above pedigree, assume that no outsider marrying in, carry a disease. Write the genotypes of $C$ and $D$.
Pick out the correct statements.
$I.$ Haemophilia is a sex-linked recessive disease
$II.$ Down's syndrome is due to aneuploidy
$III.$ Phenylketonuria is an autosomal dominant gene disorder
$IV.$ Phenylketonuria is an autosomal recessive gene disorder
$V.$ Sickle cell anaemia is an $X$-linked recessive gene disorder
Pick out the correct statements.
$I.$ Haemophilia is a sex-linked recessive disease
$II.$ Down's syndrome is due to aneuploidy
$III.$ Phenylketonuria is an autosomal dominant gene disorder
$IV.$ Phenylketonuria is an autosomal recessive gene disorder
$V.$ Sickle cell anaemia is an $X$-linked recessive gene disorder
Haemophillic man marries a normal woman. Their offsprings will be
Haemophillic man marries a normal woman. Their offsprings will be
- [AIPMT 1999]
An example of a disease of molecular mutation is
An example of a disease of molecular mutation is