A wooden block of mass $5 \mathrm{~kg}$ rests on soft horizontal floor. When an iron cylinder of mass $25$ $\mathrm{kg}$ is placed on the top of the block, the floor yields and the block and the cylinder together go down with an acceleration of $0.1 \mathrm{~ms}^{-2}$. The action force of the system on the floor is equal to:

  • [JEE MAIN 2024]
  • A

    $297 \mathrm{~N}$

  • B

    $294 \mathrm{~N}$

  • C

    $291 \mathrm{~N}$

  • D

     $196 \mathrm{~N}$

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