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A wooden block performs $SHM$ on a frictionless surface with frequency, $v_0$. The block carries a charge $+Q$ on its surface. If now a uniform electric field $\vec{E}$ is switched-on as shown, then the $SHM$ of the block will be

of the same frequency and with shifted mean position.
of the same frequency and with the same mean position.
of changed frequency and with shifted mean position.
of changed frequency and with the same mean position.
Solution
As frequency of oscillation of wooden block, $v_0=\frac{1}{2 \pi} \sqrt{\frac{k}{m}}$, does not depend on constat external force due to electric field, hence the frequency of oscillation will be the same. But due to constant external force, the mean position of the wooden block gets shifted. Hence, option $(a)$ is correct.