A zener diode having breakdown voltage equal to 5,V is used in voltage regulator circuit shown in fi

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14.Semiconductor Electronics

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A zener diode having breakdown voltage equal to $5\,V$ is used in voltage regulator circuit shown in figure, the current through diode is........$mA$

A

$100$

B

$95$

C

$150$

D

$195$

Solution

$I_{2}=\frac{5}{1}=5 \mathrm{\,mA}$

$I_{1}=\frac{20-5}{150} \times 10^{3}=100 \,m A$

Current through Zener diode $=\mathrm{I}_{1}-\mathrm{I}_{2} $

$=95 \mathrm{\,mA} $

Standard 12

Physics

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