7.Gravitation
easy

Acceleration due to gravity $'g'$ for a body of mass $'m'$ on earth's surface is proportional to (Radius of earth$=R$, mass of earth$=M$)

A

$GM/{R^2}$

B

${m^0}$

C

$mM$

D

$1/{R^{3/2}}$

Solution

$F=\frac{G M M}{R^2}=m g \Rightarrow g=\frac{G M}{R^2}$

$g \propto \frac{G M}{R^2}$

Standard 11
Physics

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