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7.Gravitation
easy
Acceleration due to gravity $'g'$ for a body of mass $'m'$ on earth's surface is proportional to (Radius of earth$=R$, mass of earth$=M$)
A
$GM/{R^2}$
B
${m^0}$
C
$mM$
D
$1/{R^{3/2}}$
Solution
$F=\frac{G M M}{R^2}=m g \Rightarrow g=\frac{G M}{R^2}$
$g \propto \frac{G M}{R^2}$
Standard 11
Physics