Acceleration versus time graph of a body starting from rest is shown in the figure. The velocity versus time graph of the body is given by
(d)
Acceleration in second case is more. Hence slope is more.
The velocity-displacement graph of a particle is shown in the figure.
The acceleration-displacement graph of the same particle is represented by :
The position$(x)$ of a particle at any time$(t)$ is given by $x(t) = 4t^3 -3t^2 + 2$ The acceleration and velocity of the particle at any time $t = 2\, sec$ are respectively
Equation of motion of a body is $\frac{d v}{d t}=-4 v+8$, where $v$ is the velocity in $m / s$ and $t$ is the time in second. Initial velocity of the particle was zero. Then,
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