Equation of motion of a body is frac{d v}{d t | vedclass

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Question

(b)

$a=\frac{d v}{d t}=-4 v+8$

$	herefore \quad \frac{d a}{d t}=-4 \cdot \frac{d v}{d t}=-(-4 v+8)$

$=16 v-32$

$\left(\frac{d a}{d t}ig

Vedclass · Accepted Answer

the terminal speed is $2\,m / s$

Vedclass · Answer

(b)

$a=\frac{d v}{d t}=-4 v+8$

$	herefore \quad \frac{d a}{d t}=-4 \cdot \frac{d v}{d t}=-(-4 v+8)$

$=16 v-32$

$\left(\frac{d a}{d t}ight)_{t=0}=-32\,m / s ^3$

At terminal velocity $a=0$

$	herefore \quad v=2\,m / s$

Equation of motion of a body is $\frac{d v}{d t}=-4 v+8$, where $v$ is the velocity in $m / s$ and $t$ is the time in second. Initial velocity of the particle was zero. Then,

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