According to MOT which of following is correc | vedclass

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Question

$(A) \,M.O.$ for $C_2=\sigma_1 s^2\,<\,\sigma_1^* s^2\,<\,\sigma_2 s^2\,<\,\sigma_2^* s^2\,<\,\underbrace{\pi_2 p_y^2=\pi_2 p_z^2}_{H O M

Vedclass · Accepted Answer

All above are correct

Vedclass · Answer

$(A) \,M.O.$ for $C_2=\sigma_1 s^2\,<\,\sigma_1^* s^2\,<\,\sigma_2 s^2\,<\,\sigma_2^* s^2\,<\,\underbrace{\pi_2 p_y^2=\pi_2 p_z^2}_{H O M O}\,<\,\underbrace{\sigma_2 p_x}_{L U M O}$

Hence, $LUMO$ is $\sigma_{2 p_x}$.

$(B)$ It is important to note that double bond in $C_2$ consists of both $pi$ bonds because of the presence of four electrons in two pi molecular orbitals.

$(C)\,C_2^{2-}$ has two $pi$ bonds and one sigma bond.

According to $MOT$ which of following is correct

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