Gujarati
4.Chemical Bonding and Molecular Structure
normal

अणु कक्षक सिद्धान्त (Molecular Orbital Theory) के अनुसार

$(A)$ $C _2^{2-}$ प्रत्याशित रूप से प्रतिचुम्बकीय (diamagnetic) है

$(B)$ $O _2$ (t) की आबंध लम्बाई (bond length) प्रत्याशित रूप से $O _2$ की आबंध लम्बाई से लम्बी है

$(C)$ $N _2^{+}$तथा $N _2^{-}$की आबंध कोटि (bond order) समान है

$(D)$ $He _2{ }^{+}$की ऊर्जा दो एकल (isolated) $He$ परमाणुओं की ऊर्जा के समान है

A

$A,D$

B

$A,C$

C

$A,B$

D

$A,D,B$

(IIT-2016)

Solution

The correct options are

$A C _2^{2-}$ is expected to be diamagnetic

$CN _2^{+}$and $N _2^{-}$have the same bond order

Total number of electrons in $C _2^{2-}$ is 14 and is diamagnetic according to MOT:

$\sigma_{1 s^2} \sigma_{1 s^2}^* \sigma_{2 s^2} \sigma_{2 s^2}^* \pi_{2 p_x^2} \pi_{2 p_y^2} \sigma_{2 p_x^2}^2$

$O _2^{2+}$ is having a bond order of 3 while $O _2$ has a bond order of 2 and thus $O _2$ is expected to have a longer bond length than $O _2^{2+}$.

Bond order of $N _2^{+}=$bond order of $N _2^{-}=2.5$

Bond order of $He _2^{+}$is $0.5$ and there will be some energy change during the formation of $He _2^{+}$from two isolated He atoms.

Standard 11
Chemistry

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