According to Molecular Orbital Theory,

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Question

The correct options are

$A C _2^{2-}$ is expected to be diamagnetic

$CN _2^{+}$and $N _2^{-}$have the same bond order

Total number of electro

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$A,C$

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The correct options are

$A C _2^{2-}$ is expected to be diamagnetic

$CN _2^{+}$and $N _2^{-}$have the same bond order

Total number of electrons in $C _2^{2-}$ is 14 and is diamagnetic according to MOT:

$\sigma_{1 s^2} \sigma_{1 s^2}^* \sigma_{2 s^2} \sigma_{2 s^2}^* \pi_{2 p_x^2} \pi_{2 p_y^2} \sigma_{2 p_x^2}^2$

$O _2^{2+}$ is having a bond order of 3 while $O _2$ has a bond order of 2 and thus $O _2$ is expected to have a longer bond length than $O _2^{2+}$.

Bond order of $N _2^{+}=$bond order of $N _2^{-}=2.5$

Bond order of $He _2^{+}$is $0.5$ and there will be some energy change during the formation of $He _2^{+}$from two isolated He atoms.

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