According to reaction PbC{l₂} = P{b^2} + 2C{l^ - }, solubility coefficient of PbC{l₂} is

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6-2.Equilibrium-II (Ionic Equilibrium)

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According to the reaction $PbC{l_2} = P{b^2} + 2C{l^ - },$the solubility coefficient of $PbC{l_2}$ is

A

$[P{b^{2 + }}]\,{[C{l^ - }]^2}$

B

$[P{b^{2 + }}]\,[C{l^ - }]$

C

${[P{b^{2 + }}]^2}\,[C{l^ - }]$

D

None of these

Solution

(a) Solubility coefficient $ = [P{b^{2 + }}]\,\,{[C{l^ – }]^2}$

Standard 11

Chemistry

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(KVPY-2014)