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6-2.Equilibrium-II (Ionic Equilibrium)
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When $1.88 \,g$ of $AgBr (s)$ is added to a $10^{-3} \,M$ aqueous solution of $KBr$, the concentration of $Ag ^{+}$is $5 \times 10^{-10}\, M$. If the same amount of $AgBr (s)$ is added to a $10^{-2}\, M$ aqueous solution of $AgNO _3$, the concentration of $Br ^{-}$ is
A$9.4 \times 10^{-9}\, M$
B$5 \times 10^{-10} \,M$
C$1 \times 10^{-11} \,M$
D$5 \times 10^{-11} \,M$
(KVPY-2014)
Solution
(d)
$AgBr \rightleftharpoons Ag ^{+}\quad+\quad Br ^{-}$
$\quad\quad\quad 5 \times 10^{-10}M \quad\, 10^{-3}\, M$
$K_{ sp }=\left[ Ag ^{+}\right]\left[ Br ^{-}\right]$
$=\left(5 \times 10^{-10} M)( 10^{-3}M)\, \right.$
$=5 \times 10^{-13}$
If same amount of $\operatorname{AgBr}(s)$ is added to a $10^{-2}\, M$ aqueous solution of $AgNO _3$, then the concentration of $Ag ^{+}=10^{-2}\, M$
$\therefore 5 \times 10^{-13}=\left[10^{-2}\right]\left[ Br ^{-}\right]$
${\left[ Br ^{-}\right]=5 \times 10^{-11}\, M }$
$AgBr \rightleftharpoons Ag ^{+}\quad+\quad Br ^{-}$
$\quad\quad\quad 5 \times 10^{-10}M \quad\, 10^{-3}\, M$
$K_{ sp }=\left[ Ag ^{+}\right]\left[ Br ^{-}\right]$
$=\left(5 \times 10^{-10} M)( 10^{-3}M)\, \right.$
$=5 \times 10^{-13}$
If same amount of $\operatorname{AgBr}(s)$ is added to a $10^{-2}\, M$ aqueous solution of $AgNO _3$, then the concentration of $Ag ^{+}=10^{-2}\, M$
$\therefore 5 \times 10^{-13}=\left[10^{-2}\right]\left[ Br ^{-}\right]$
${\left[ Br ^{-}\right]=5 \times 10^{-11}\, M }$
Standard 11
Chemistry
