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6.Interest
hard
Aditya invest $Rs. 50,000$ in a fixed deposit at $10 \%$ $C.I.$ for $2$ years. At the end of $2$ years she put the money in another deposit at $12 \%$ $S.I.$ for $3$ years. What was the final value (In $Rs.$) of the initial Investment?
A
$80000$
B
$81280$
C
$82280$
D
$83280$
Solution
CI for first 2 years
$=50000\left[\left(1+\frac{10}{100}\right)^{2}-1\right]=\operatorname{Rs} .10500$
Amount $= P + CI =50000+10500= Rs .60500$
$SI =\frac{ P \times R \times T }{100}=\frac{60500 \times 12 \times 3}{100}= Rs .21780$
Total amount $=$ $Rs. 82280$
Standard 13
Quantitative Aptitude
