After absorbing a slowly moving neutron of mass $m_N$  $(momentum $~ $0)$ a nucleus of mass $M$ breaks into two nuclei of masses $m_1$ and $3m_1$ $(4m_1 = M + m_N)$, respectively. If the de Broglie wavelength of the nucleus with mass $m_1$ is $\lambda$, then de Broglie wavelength of the other nucleus will be

  • A

    $9 \lambda$ 

  • B

    $3 \lambda$

  • C

    $\frac{\lambda }{3}$

  • D

    $\lambda$ 

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  • [KVPY 2012]