In uranium radioactive series, initial nucleus is _{92}{U^{238}} and final nucleus is _{82}P{b^{206}

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13.Nuclei

easy

In the uranium radioactive series, the initial nucleus is $_{92}{U^{238}}$ and the final nucleus is $_{82}P{b^{206}}$. When the uranium nucleus decays to lead, the number of $\alpha - $ particles emitted will be

A

$1$

B

$2$

C

$4$

D

$8$

Solution

(d) ${n_\alpha } = \frac{{A – A'}}{4} = \frac{{238 – 206}}{4} = 8$

Standard 12

Physics

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