Aluminium $(III)$ chloride forms a dimer because
Aluminium $(III)$ chloride forms a dimer because
- [AIPMT 1995]
- A
Higher coordination number can be achieved by aluminium
- B
Aluminium has high ionization energy
- C
Aluminium belongs to $III$ group
- D
It cannot form a trimer
Similar Questions
Boron does not form $B^{3+}$ cation easily. it is due to
Boron does not form $B^{3+}$ cation easily. it is due to
The element which exists in liquid state for a wide range of temperature and can be used for measuring high temperature is :-
The element which exists in liquid state for a wide range of temperature and can be used for measuring high temperature is :-
The correct statements from the following are :
$(A)$ The decreasing order of atomic radii of group $13$ elements is $\mathrm{Tl}>\mathrm{In}>\mathrm{Ga}>\mathrm{Al}>\mathrm{B}$.
$(B)$ Down the group $13$ electronegativity decreases from top to bottom.
$(C)$ $\mathrm{Al}$ dissolves in dil. $\mathrm{HCl}$ and liberate $\mathrm{H}_2$ but conc. $\mathrm{HNO}_3$ renders Al passive by forming a protective oxide layer on the surface.
$(D)$ All elements of group 13 exhibits highly stable +1 oxidation state.
$(E)$ Hybridisation of $\mathrm{Al}$ in $\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}$ ion is $\mathrm{sp}^3 \mathrm{~d}^2$.
Choose the correct answer from the options given below:
The correct statements from the following are :
$(A)$ The decreasing order of atomic radii of group $13$ elements is $\mathrm{Tl}>\mathrm{In}>\mathrm{Ga}>\mathrm{Al}>\mathrm{B}$.
$(B)$ Down the group $13$ electronegativity decreases from top to bottom.
$(C)$ $\mathrm{Al}$ dissolves in dil. $\mathrm{HCl}$ and liberate $\mathrm{H}_2$ but conc. $\mathrm{HNO}_3$ renders Al passive by forming a protective oxide layer on the surface.
$(D)$ All elements of group 13 exhibits highly stable +1 oxidation state.
$(E)$ Hybridisation of $\mathrm{Al}$ in $\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}$ ion is $\mathrm{sp}^3 \mathrm{~d}^2$.
Choose the correct answer from the options given below:
- [JEE MAIN 2024]
Mention isotops of boron.
Mention isotops of boron.
Match List $I$ with List $II$. Choose the correct answer from the options given below:
List $-I$
List $-II$
$A.$ Melting point $[\mathrm{K}]$
$I.$ $\mathrm{Tl}>\mathrm{In}>\mathrm{Ga}>\mathrm{Al}>\mathrm{B}$
$B.$ Ionic Radius $\left[\mathrm{M}^{+3} / \mathrm{pm}\right]$
$II.$ $\mathrm{B}>\mathrm{Tl}>\mathrm{Al} \approx \mathrm{Ga}>\mathrm{In}$
$C.$ $\Delta_{\mathrm{i}} \mathrm{H}_1 $ $ [\mathrm{~kJ} \mathrm{~mol}^{-1}]$
$III.$ $\mathrm{Tl}>\mathrm{In}>\mathrm{Al}>\mathrm{Ga}>\mathrm{B}$
$D.$ Atomic Radius $[pm]$
$IV.$ $\mathrm{B}>\mathrm{Al}>\mathrm{Tl}>\mathrm{In}>\mathrm{Ga}$
Match List $I$ with List $II$. Choose the correct answer from the options given below:
| List $-I$ | List $-II$ |
|
$A.$ Melting point $[\mathrm{K}]$ |
$I.$ $\mathrm{Tl}>\mathrm{In}>\mathrm{Ga}>\mathrm{Al}>\mathrm{B}$ |
|
$B.$ Ionic Radius $\left[\mathrm{M}^{+3} / \mathrm{pm}\right]$ |
$II.$ $\mathrm{B}>\mathrm{Tl}>\mathrm{Al} \approx \mathrm{Ga}>\mathrm{In}$ |
| $C.$ $\Delta_{\mathrm{i}} \mathrm{H}_1 $ $ [\mathrm{~kJ} \mathrm{~mol}^{-1}]$ | $III.$ $\mathrm{Tl}>\mathrm{In}>\mathrm{Al}>\mathrm{Ga}>\mathrm{B}$ |
| $D.$ Atomic Radius $[pm]$ | $IV.$ $\mathrm{B}>\mathrm{Al}>\mathrm{Tl}>\mathrm{In}>\mathrm{Ga}$ |
- [JEE MAIN 2024]