p-Block Elements - I
medium

Aluminum dissolves in mineral acids and aqueous alkalis and thus shows amphoteric character. A piece of aluminum foil is treated with dilute hydrochloric acid or dilute sodium hydroxide solution in a test tube and on bringing a burning match stick near the mouth of the test tube, a pop sound indicates the evolution of hydrogen gas. The same activity when performed with concentrated nitric acid, reaction doesn't proceed. Explain the reason. 

Option A
Option B
Option C
Option D

Solution

Aluminum is amphoteric in nature, it reacts with acid and base to give salt and $\mathrm{H}_{2}$ gas. It burns with pop sound.

$2 \mathrm{Al}+6 \mathrm{HCl} \rightarrow 2 \mathrm{AlCl}_{3}+3 \mathrm{H}_{2}$

$2 \mathrm{Al}+\mathrm{NaOH}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{NaAlO}_{2}+3 \mathrm{H}_{2}$

When $\mathrm{Al}$ reacts with conc. $\mathrm{HNO}_{3}$, a thin layer of $\mathrm{Al}_{2} \mathrm{O}_{3}$ on the surface of $\mathrm{Al}$ metal which protect further reaction. This layer is called protective layer.

$2 \mathrm{Al}+6 \mathrm{HNO}_{3} \rightarrow \mathrm{Al}_{2} \mathrm{O}_{3}+6 \mathrm{NO}_{2}+3 \mathrm{H}_{2} \mathrm{O}$

Standard 11
Chemistry

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