Aluminium chloride exists as dimer, $A{l_2}C{l_6}$ in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives
Aluminium chloride exists as dimer, $A{l_2}C{l_6}$ in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives
- [AIEEE 2004]
- A
${[Al{(OH)_6}]^{3 - }} + 3HCl$
- B
${[Al{({H_2}O)_6}]^{3 + }} + 3HCl$
- C
$A{l^{3 + }} + 3C{l^ - }$
- D
$A{l_2}{O_3} + 6HCl$
Similar Questions
$N{a_2}{B_4}{O_7}.10{H_2}O\xrightarrow{{Heat}}X + NaB{O_2} + {H_2}O,X + C{r_2}{O_3}\xrightarrow{{Heat}}\mathop Y\limits_{\left( {Green\,coloured} \right)} $ $X$ and $Y$ are
$N{a_2}{B_4}{O_7}.10{H_2}O\xrightarrow{{Heat}}X + NaB{O_2} + {H_2}O,X + C{r_2}{O_3}\xrightarrow{{Heat}}\mathop Y\limits_{\left( {Green\,coloured} \right)} $ $X$ and $Y$ are
Give chemical reaction of aluminum with dilute $HCl$ ?
Give chemical reaction of aluminum with dilute $HCl$ ?
Given below are the statements about diborane.
$(a)$ Diborane is prepared by the oxidation of $\mathrm{NaBH}_{4}$ with $\mathrm{I}_{2}$.
$(b)$ Each boron atom is in sp $^{2}$ hybridized state.
$(c)$ Diborane has one bridged $3$ centre$-2-$electron bond.
$(d)$ Diborane is a planar molecule.
The option with correct statement(s) is :
Given below are the statements about diborane.
$(a)$ Diborane is prepared by the oxidation of $\mathrm{NaBH}_{4}$ with $\mathrm{I}_{2}$.
$(b)$ Each boron atom is in sp $^{2}$ hybridized state.
$(c)$ Diborane has one bridged $3$ centre$-2-$electron bond.
$(d)$ Diborane is a planar molecule.
The option with correct statement(s) is :
- [JEE MAIN 2021]
In the electrolytic extraction of aluminium, cryolite is used
In the electrolytic extraction of aluminium, cryolite is used
Anhydrous $AlC{l_3}$ is obtained from
Anhydrous $AlC{l_3}$ is obtained from