- Home
- Standard 11
- Chemistry
4.Chemical Bonding and Molecular Structure
medium
Among $\mathrm{H}_2, \mathrm{He}_2^{+}, \mathrm{Li}_2, \mathrm{Be}_2, \mathrm{~B}_2, \mathrm{C}_2, \mathrm{~N}_2, \mathrm{O}_2^{-}$, and $\mathrm{F}_2$, the number of diamagnetic species is (Atomic numbers: $\mathrm{H}=1, \mathrm{He}=2, \mathrm{Li}=3, \mathrm{Be}=4, \mathrm{~B}=5, \mathrm{C}=6, \mathrm{~N}=7, \mathrm{O}=8, \mathrm{~F}=9$ )
A
$4$
B
$8$
C
$6$
D
$5$
(IIT-2017)
Solution
$\mathrm{H}_2, \mathrm{Li}_2, \mathrm{Be}_2, \mathrm{C}_2, \mathrm{~N}_2$ and $\mathrm{F}_2$ are diamagnetic species.
$*$ However because $\mathrm{Be}_2$ does not exits the answer may well be $5$
Standard 11
Chemistry
