An α particle and a proton travel with same velocity in a magnetic field perpendicular to direction

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4.Moving Charges and Magnetism

medium

An $\alpha $ particle and a proton travel with same velocity in a magnetic field perpendicular to the direction of their velocities, find the ratio of the radii of their circular path

$4:1$

$1:4$

$2:1$

$1:2$

(AIIMS-2004)

Solution

(c) $r = \frac{{mv}}{{qB}} \Rightarrow \frac{{{r_\alpha }}}{{{r_p}}} = \frac{{{m_\alpha }}}{{{m_p}}} \times \frac{{{q_p}}}{{{q_\alpha }}} = \frac{4}{1} \times \frac{1}{2} = \frac{2}{1}$

Standard 12

Physics

Give expression for the force on a current carrying conductor in a magnetic field.

hard

A negatively charged particle projected towards east is deflected towards north by a magnetic field. The field may be

easy

Two parallel wires in the plane of the paper are distance $X _0$ apart. A point charge is moving with speed $u$ between the wires in the same plane at a distance $X_1$ from one of the wires. When the wires carry current of magnitude $I$ in the same direction, the radius of curvature of the path of the point charge is $R_1$. In contrast, if the currents $I$ in the two wires have direction opposite to each other, the radius of curvature of the path is $R_2$.

If $\frac{x_0}{x_1}=3$, the value of $\frac{R_1}{R_2}$ is.

normal

(IIT-2014)

Two protons move parallel to each other, keeping distance $r$ between them, both moving with same velocity $\vec V\,$. Then the ratio of the electric and magnetic force of interaction between them is