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9-1.Fluid Mechanics
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An air bubble of $1\, cm$ radius is rising at a steady rate of $2.00\, mm/sec$ through a liquid of density $1.5\, gm$ per $cm^3$. Neglect density of air. If $g$ is $1000\, cm/sec^2$, then the coefficient of viscosity of the liquid is
A
$0.166\times10^3\, poise$
B
$166\times10^3\, poise$
C
$1.66\times10^3\, poise$
D
$16.6\times10^3\, poise$
Solution
$\mathrm{V}_{\mathrm{T}}=\frac{2}{9} \mathrm{r}^{2} \mathrm{g}\left[\frac{\rho_{\mathrm{liquid}}}{\eta}\right]$
$0.2=\frac{2}{9} \times 1^{2} \times 1000\left[\frac{1.5}{\eta}\right]$
$\eta=1.5 \times \frac{10^{3}}{0.9}$
$\eta=1.66 \times 10^{3}$ poise
Standard 11
Physics
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