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4-1.Newton's Laws of Motion
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An army vehicle of mass $1000\, kg$ is moving with a velocity of $10 \,m/s$ and is acted upon by a forward force of $1000\, N$ due to the engine and a retarding force of $500 \,N$ due to friction. ........... $m/s$ will be its velocity after $10\, s$
A$5$
B$10$
C$15 $
D$20 $
Solution
(c)$v = u + \frac{F}{m}t = 10 + \left( {\frac{{1000 – 500}}{{1000}}} \right) \times 10 = 15\,m/s$
Standard 11
Physics
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