An athlete in the olympic games covers a dist | vedclass

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Question

The average speed of the athelete

$v = \frac{{100}}{{10}} = 10\,m/s\,\,\,\,\,\,	herefore \,K.E. = \frac{1}{2}m{v^2}$

If mass is $40$ $kg$ then,

Vedclass · Accepted Answer

$2000J -5000 J$

Vedclass · Answer

The average speed of the athelete

$v = \frac{{100}}{{10}} = 10\,m/s\,\,\,\,\,\,	herefore \,K.E. = \frac{1}{2}m{v^2}$

If mass is $40$ $kg$ then, $K.E = \frac{1}{2} 	imes 40 	imes {\left( {10} ight)^2} = 2000\,J$

If mass is $100$ $kg$ then $K.E = \frac{1}{2} 	imes 100 	imes {\left( {10} ight)^2}$ = 5000 J

An athlete in the olympic games covers a distance of $100\ m$ in $10\ s$. His kinetic energy can be estimated to be in the range

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