The kinetic energy of a body of mass $3 \,kg$ and momentum $2 \,N-s$ is
$1 \,J$
$\frac{2}{3}J$
$\frac{3}{2}J$
$4 \,J$
(b)$E = \frac{{{P^2}}}{{2m}} = \frac{4}{{2 \times 3}} = \frac{2}{3}J$
Two masses of $1 \,gm$ and $4 \,gm$ are moving with equal kinetic energies. The ratio of the magnitudes of their linear momenta is
A particle of mass $ M$ is moving in a horizontal circle of radius $R$ with uniform speed $V$. When it moves from one point to a diametrically opposite point, its
When kinetic energy of a body becomes $36$ times of its original value, the percentage increase in the momentum of the body will be :
Masses of two substances are $1\, g$ and $9\, g$ respectively. If their kinetic energies are same, then the ratio of their momentum will be
Two bodies of masses $m$ and $4 \,m$ are moving with equal $K.E.$ The ratio of their linear momentums is
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