The kinetic energy of a body of mass $3 \,kg$ and momentum $2 \,N-s$ is
$1 \,J$
$\frac{2}{3}J$
$\frac{3}{2}J$
$4 \,J$
Two bodies of masses ${m_1}$ and ${m_2}$ have equal kinetic energies. If ${p_1}$ and ${p_2}$ are their respective momentum, then ratio ${p_1}:{p_2}$ is equal to
The adjoining diagram shows the velocity versus time plot for a particle. The work done by the force on the particle is positive from
Four particles $A, B, C, D$ of mass $\frac{\mathrm{m}}{2}, \mathrm{~m}, 2 \mathrm{~m}, 4 \mathrm{~m}$, have same momentum, respectively. The particle with maximum kinetic energy is:
A bomb of mass $3.0\, Kg$ explodes in air into two pieces of masses $2.0 \,kg$ and $1.0\, kg$. The smaller mass goes at a speed of $80 m/s$.The total energy imparted to the two fragments is ............. $kJ$
A bomb is kept stationary at a point. It suddenly explodes into two fragments of masses $1\, g$ and $3\;g$. The total K.E. of the fragments is $6.4 \times {10^4}J$. What is the K.E. of the smaller fragment