An average force of 125,N is applied on a machine gun firing bullets each of mass 10,g at speed of 2

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4-1.Newton's Laws of Motion

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An average force of $125\,N$ is applied on a machine gun firing bullets each of mass $10\,g$ at the speed of $250\,m / s$ to keep it in position. The number of bullets fired per second by the machine gun is:

A

$5$

B

$50$

C

$100$

D

$25$

(JEE MAIN-2023)

Solution

$F = n mv$

where $n =$ number of bullets fired per second

$n =\frac{ f }{ mv }=\frac{125}{10 \times 10^{-3} \times 250}=50$

Standard 11

Physics

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