1. Electric Charges and Fields
easy

An electric charge $q$ is placed at the centre of a cube of side $\alpha $. The electric flux on one of its faces will be

A

$\frac{q}{{6{\varepsilon _0}}}$

B

$\frac{q}{{{\varepsilon _0}{a^2}}}$

C

$\frac{q}{{4\pi {\varepsilon _0}{a^2}}}$

D

$\frac{q}{{{\varepsilon _0}}}$

(AIIMS-2001)

Solution

(a) By Gauss's theorem.

Net flux through the cube ${\varphi _{net}} = \frac{Q}{{{\varepsilon _0}}};$ so flux through one face ${\varphi _{face}} = \frac{q}{{6{\varepsilon _0}}}$

Standard 12
Physics

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