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1. Electric Charges and Fields
easy
An electric charge $q$ is placed at the centre of a cube of side $\alpha $. The electric flux on one of its faces will be
A
$\frac{q}{{6{\varepsilon _0}}}$
B
$\frac{q}{{{\varepsilon _0}{a^2}}}$
C
$\frac{q}{{4\pi {\varepsilon _0}{a^2}}}$
D
$\frac{q}{{{\varepsilon _0}}}$
(AIIMS-2001)
Solution
(a) By Gauss's theorem.
Net flux through the cube ${\varphi _{net}} = \frac{Q}{{{\varepsilon _0}}};$ so flux through one face ${\varphi _{face}} = \frac{q}{{6{\varepsilon _0}}}$
Standard 12
Physics